121z^2=25

Solution for 121z^2=25 equation:

121z^2=25

We move all terms to the left:

121z^2-(25)=0

a = 121; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·121·(-25)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*121}=\frac{-110}{242}
=-5/11
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*121}=\frac{110}{242}
=5/11
$